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#1
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The end of the resistor body with the stripe is the + end. Start with about 50 ohms, at least 5 watts, and adjust from there. Sets with voltage doublers for the main B+ need a smaller resistor (typically 10-20 ohms, 10 watts) but I believe in this set that rectifier carries a smaller load. The added resistor simply goes in series with the diode, either before or after.
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#2
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There are, obviously, two leads connected to the selenium rectifier. One to the positive marked end, and one to the negative. I take it the diode connects in similar fashion.
Does the 50 ohm resistor go between the negative lead to the diode or the positive? Thanks. PS: It's been awhile since I've done this. |
#3
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Dumb as it seems, the '+' end of the selenium corresponds to the banded (cathode) end of the Si diode. The + sign simply means "the B plus comes out of here".
The resistor would connect "upstream" of the diode. |
#4
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I should try proofreading some time.
The end of the diode with the stripe is the + end. The added resistor goes on either side -- it doesn't matter which you choose. |
#5
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Which side doesn't matter, but conventionally it went on the input side of the diode.
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Audiokarma |
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