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also, this thing has the so called "ballast tube" that needs replacing. a couple of those filiment resistors are burned open, and there are others that are intact.
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Do all the tubes' heaters light up, or just one of the strings? In any event, if a string's voltage adds up to about 85V, you could use a diode (like an 1N4004) with no filter cap to run that string off the 120V powerline. Remember that it's V^2/R = power, and that a diode would cut that power by half. So (1/2)(120V^2)/R =~ (85V^2)/R Tubes generally perfer that their heaters are on average at more positive voltage than their cathodes, so connect the diode's cathode to the top of the string.
If the string adds up to less than 85V, pad it up with a power resistor of appropiate size. using the heater string's rated current, and the amount of voltage you need to make it add up to 85V, R=V/I. And the power size needed: I^2*R =P This cuts waste heat down.