Quote:
Originally Posted by old_coot88
Dang, that is a good question at first thought. But apparently, since there's no DC return path to the HV supply, the electons' total energy is being absorbed and re-emitted as light.
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There IS a DC return path, or the phosphor would eventually charge negative to the point where no electrons would land. The question here is to identify the return path, which I think is via secondary emission. I also think that in the case of a non-aluminized tube, the secondary electrons go to the internal dag, and in an aluminized tube they just go to the aluminum coating.