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Even if it is a series string, the filaments do not come into play - they are a separate leg/circuit. The total load coming from the doubler cannot exceed the ampere rating of the original seleniums, which Tim stated was about 320mA.
Second, the voltage drop across the selenium is rarely above 5V, and with the 7/10s of a volt that a silicon diode drops, you only have to drop the additional 4.3V or so. You aren't dropping tens or hundreds of extra volts, so the resistance and wattage are going to be low.
I stand by the calculations - two previous posters also weighed in, saying 25 watts is overkill - and I too have never used more than a ten watt resistor. In any case, it is imperative that the set be fused, and adding a B+ fuse would also be recommended.
60 bucks for a 20 watt resistor(s)? Where? Three 5 watt resistors could be had for a buck-thirty plus shipping.
I too can sense Tim's confusion -and a good reference for replacing seleniums is nowhere on the web. It's all Ohms Law and Kirchoffs Law, but no one on the web applies either to a selenium replacement scenario. I guess someday they'll all be replaced, making this thread obsolete.
Cheers,
__________________
Brian
USN RET 22YRS (Avionics/Cal)
CET-Consumer Repair and Avionics ('88)
"Capacitor Cosmetologist since '79"
When fuses go to work, they quit!
Last edited by Findm-Keepm; 11-07-2013 at 04:22 AM.
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