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Old 11-23-2013, 02:23 PM
Kevin Kuehn's Avatar
Kevin Kuehn Kevin Kuehn is offline
Workin' Late Again
 
Join Date: Jan 2011
Location: WI
Posts: 3,976
Pin 2,5 should be about half of whatever's on pin 6 - because the voltage on pin 6 should be basically divided in half by the 470k and 560k resistors in series going to ground. The grid(pins2-5) get's it's bias from the junction of those two resistors. Not sure why your source feeding pin 6 is so high. You might go back and measure the AC voltage on pins 4,6 of the 5Y3. Suppose to be 240vac from each pin to ground. Then 240vdc on pins 2,8.

Last edited by Kevin Kuehn; 11-23-2013 at 02:27 PM.
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