Quote:
Originally Posted by Alex KL-1
The diode only will serve to make a voltage offset; will not isolate anything (unless the focus grid supply current...). Is better to invest in the resistor values.
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Okay, I thought the current loading was the issue, but I guess you're saying that it's actually a voltage drop on the screen?
The issue I'm having with this is that when I put the 1M pot in the circuit with the other side to ground, it creates a load on the screen supply and the screen dims. I thought it was a current issue, but I guess it would make sense that it's creating an additional resistive divider for the screen potentiometer. There is a lot going on in this circuit, and I'm having trouble visualizing exactly what happens when I put the pot in. It's like this, and the arrow is where I would put the proposed diode in place:
Otherwise, are you saying that I can prevent the voltage drop by using a higher value resistor to supply the Focus Grid, with another one to ground on the other side? I think I mainly need help understanding exactly why the G2 is becoming dim in order to fix it because I don't know how to do the calculations for the resistors if that is so.