Blunderof the Week

[dieseljeep]

Originally Posted by Electronic M

To determine the wattage take the heater current and multiply it by (120V - the sum of the heater voltages of the tubes in series with your resistor)...Or, if I'm interpreting the info you posted correctly, 0.15A*(120-35V)=12.75W....Go with a 13W or higher replacement.

There are also ways to replace the cord with a diode or a capacitor to drop the voltage, which have the advantage of not releasing nearly as much heat. You will have to google those as I'm not experienced enough with those methods to specifically advise you off the top of my head.

Hey Tom!
Look up WA2ISE's website.
His formula for cap droppers is real easy to use and I've had great sucess with my applications.

[Electronic M]

Originally Posted by dieseljeep

Hey Tom!
Look up WA2ISE's website.
His formula for cap droppers is real easy to use and I've had great sucess with my applications.

Thanks for the advise. I've never worked on a resistance line cord set before so I've never needed to do this. Odds are that on a good day I could remember the correct formula and solve it, but I don't want to advise someone off the top of my head on something critical like that, and lacked the time to confirm correctness through research at the time of that post...