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I=E/R R=E/I E=IR Where I= Intensity (current in amps) R=Resistance (in ohms) E=Electromotive force (voltage) So if you have a 33K (33,000 ohm) resistor and current thru it is 4.4 ma. (.0044 amp) What is the voltage across the resistor? |
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In fact most modern Digital Multi-Meters (DMMs) use that principle. In my freshman year of college I built a digital multimeter kit and it used that exact principle. It had a short length of thick wire shorting the + and - current measurement terminals and we had to adjust the length of wire that we soldered between those terminals so that it was exactly 1 Ohm. At that value 2A through it meant 2V across it, 1A -> a 1V drop and so on. The circuit simply measured the voltage drop across that wire that shorted the current measurement terminals and scaled the value according to the range it was set to. |
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